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500=1.5x^2
We move all terms to the left:
500-(1.5x^2)=0
We get rid of parentheses
-1.5x^2+500=0
a = -1.5; b = 0; c = +500;
Δ = b2-4ac
Δ = 02-4·(-1.5)·500
Δ = 3000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3000}=\sqrt{100*30}=\sqrt{100}*\sqrt{30}=10\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{30}}{2*-1.5}=\frac{0-10\sqrt{30}}{-3} =-\frac{10\sqrt{30}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{30}}{2*-1.5}=\frac{0+10\sqrt{30}}{-3} =\frac{10\sqrt{30}}{-3} $
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